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6x^2+63x+120=0
a = 6; b = 63; c = +120;
Δ = b2-4ac
Δ = 632-4·6·120
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-33}{2*6}=\frac{-96}{12} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+33}{2*6}=\frac{-30}{12} =-2+1/2 $
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